Question

Find the equation of the line that passes through (1,6) and (3,10).

y=2x+4
y=-2x+4
y=-24-4
Oy-23-4

Answer 1

m = (y2 - y1) / (x2 - x1) = (10 - 6) / (3 - 1) = 2 slope of line

y = m x + b standard form of straight line

y = 2 x + b where b is the intercept at x = 0

b = y - 2 x

b = 6 - 2 = 4 from our first equation

Also, b = 10 - 6 = 4 check from second equation

y = 2 x + 4 is our equation

Check if y = 6 and x = 1 then

y = 2 * 1 + 4 = 6 verifying the first point given