Question

An inductor has an inductance of 0.053 H. The voltage across this inductor is 48 V and has a frequency of 270 Hz. What is the current in the inductor?

Answer 1

3.004A

Step-by-step explanation:

The voltage across an inductor is expressed as:

`V=IX_L\\V=I(2\pi fL)`

Given

f = 270Hz

V = 48V

L =0.053 H

Get the current

270 = I (2*3.14*270*0.053)

270 = 89.8668I

I = 270/89.8668

I = 3.004A

Hence the current in the inductor is 3.004A