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Find and sketch the domain of the function. f(x,y)=√(4-x^2-y^2) +√(1-x^2)


User Shaakira
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Answer:

Hello

Explanation:

The domain is limited with 2 lines parallel: -1 ≤ x ≤ 1

and the disk ? (inside of a circle) of center (0,0) and radius 2


dom\ f(x,y)=\{(x,y) \in \mathbb{R} ^2 | \ -1\leq x \leq -1\ and \ ( -√(4-x^2) \leq \ y \leq √(4-x^2)\ ) \ \}\\

Find and sketch the domain of the function. f(x,y)=√(4-x^2-y^2) +√(1-x^2) ​-example-1
User Mrinmoy Ghoshal
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