Question

What is the change in velocity of a 22-kg object that experiences a force of 15 N for

1.2 seconds?

Answer 1

Force = mass × acceleration

Acceleration:

`{ \tt{15 = (22 * a)}} \\ { \tt{a = (15)/(22) \: {ms}^( - 2) }}`

From first Newton's equation of motion:

`{ \bf{v = u + at}}`

Change = v - u:

`{ \tt{v - u = (a * t)}} \\ { \tt{v - u = ( (15)/(22) * 1.2) }} \\ { \tt{v - u = 0.82 \: {ms}^( - 2) }}`