Question

For a gas sample containing equimolar amounts of carbon monoxideand heliumat 300 K, heliumhas _____________average speed and _____________ average kinetic energy compared tocarbon monoxidegas.a.a lower; the same b. the same; the same c. a higher; the same d. a higher; higher

Answer 1

At the same temperature, helium has a higher average speed but the same average kinetic energy as carbon monoxide due to its lighter atomic mass.

Step-by-step explanation:

When comparing a gas sample containing equimolar amounts of carbon monoxide (CO) and helium (He) at 300 K, we can apply the principles of kinetic molecular theory. According to this theory, at a given temperature, all gases have the same average kinetic energy (KEavg). However, because helium atoms are lighter than carbon monoxide molecules, at the same temperature, helium will have a higher average speed.

The correct answer to the question is that helium has a higher average speed and the same average kinetic energy compared to carbon monoxide gas. Therefore, the best choice is c. a higher; the same.

For a gas sample containing equimolar amounts of carbon monoxide and helium at 300 K, helium has the same average speed and the same average kinetic energy compared to carbon monoxide gas.

Answer 2

Option C (a higher; the same) is the appropriate response.

Step-by-step explanation:

Given:

Temperature,

T = 300 K (both
`N_2` and
`H_2`)

As we know,

Average speed of a molecule,

⇒
`\bar v=\sqrt{(8RT)/(\pi M) }`

Thus, the average speed of
`N_2` will be lower as its molar mass is greater than
`H_2`.

Now,

⇒
`Average \ kinetic \ energy = (3)/(2) \ KT` (not depend on molar mass)

Hence, it will be the same.

The other three alternatives aren't connected to the scenario given. So the above is the correct answer.