Question

The length of a rectangle is 4 in longer than its width.

If the perimeter of the rectangle is 32 in, find its area.

Answer 1

60 sq in

Explanation:

Perimeter = 2l + 2w

If l = w+4

Perimeter = 2(w+4) + 2w

Perimeter = 4w+8

32 = 4w + 8

24 = 4w

6 = w

If w = 6, l = 6+4 = 10

Area = l * w

Area = 10 * 6

Area = 60