Question

What’s the equation of a line that goes through the point (0, -3/5) and has a slope of -1?

Answer 1

`\large{ \tt{ ✽ \: S \: O \: L \: U \: T \: I \: O \: N: }}`

• We're provided : Point A [ Let's suppose ] ( 0 , -3/5 ) and slope = -1 and we're asked to find out the equation of a line having these point and slope. Let A ( 0 , -3/5 ) be ( x₁ , y₁ ).Firstly , You'll have to know : y - y₁ = m ( x - x₁ )

`\large{ \tt{✺ \: S \: O \: L \: V \: I \: N \: G \: ...}}`

`❁ \: \large{ \tt{y - y_(1) = m(x - x_(1) )}}`

`\large{ \tt{⟶ \: y - ( - (3)/(5) ) = - 1(x - 0)}}`

`\large{ \tt{⟶ \: y + (3)/(5) = - x + 0}}`

`\large {\tt{⟶ \: (5y + 3)/(5 ) = - x }}`

`\large{ \tt{⟶ \: 5y + 3 = - 5x}}`

`\boxed{\large{ \tt{⟶5x + 5y + 3 = 0}}}`

• Hence , 5x + 5y + 3 = 0 is the required equation.

• Hope I helped! Let me know if you have any question regarding my answer and also don't hesitate to reach out to me if you need any other help! :)

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