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The graph of which function has a minimum located at (4, -3)?
O f(x) = - 5x2 + 4x - 11
f(x) = -2x? + 16x -35
O f(x) = 4x2 - 4x + 5
O f(x) = 2x2 - 16x + 35

User Juicy
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1 Answer

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Answer:

(d) f(x) = 2x^2 - 16x + 35

Explanation:

The x-coordinate of the extreme will be found at ...

x = -b/(2a)

where the function is f(x) = ax²+bx+c.

The extreme will be a minimum when a > 0. (eliminates choices A and B)

The x-coordinates of the extremes are ...

C: -(-4)/(2(4)) = 1/2

D: -(-16)/(2(2)) = 4 . . . . . matches the requirement

The appropriate choice is ...

f(x) = 2x^2 - 16x + 35

User Jgonian
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