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Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do not show that

Rn(x) → 0.] Find the associated radius of convergence R.
f(x) = 8(1 − x)^−2
show step by step including finding the derivatives.

User Uzyn
by
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1 Answer

1 vote

Recall that for |x| < 1, we have


\displaystyle \frac1{1-x} = \sum_(n=0)^\infty x^n

Differentiating both sides gives


\displaystyle \frac1{(1-x)^2} = \sum_(n=0)^\infty nx^(n-1) = \sum_(n=0)^\infty (n+1)x^n

and multiplying both sides by 8 gives the series for f(x) :


f(x)=\displaystyle \frac8{(1-x)^2} = \boxed{8\sum_(n=0)^\infty (n+1)x^n}

and this converges over the same interval, |x| < 1, so that the radius of convergence is 1.

User Mingchaoyan
by
7.2k points
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