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What is the vertex of the quadratic function below? y=x^2-8+1

User Wowonline
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1 Answer

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9514 1404 393

Answer:

(4, -15)

Explanation:

We assume you want the vertex of ...

y = x² -8x +1

We can add and subtract 16 to complete the square.

y = x² -8x +16 +1 -16

y = (x -4)² -15

Compare to the vertex form ...

y = (x -h)² +k . . . . . . . quadratic with vertex (h, k)

We see that the vertex of the given function is ...

(h, k) = (4, -15)

What is the vertex of the quadratic function below? y=x^2-8+1-example-1
User Stinkycheeseman
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5.2k points