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Find the value of x. Round to the nearest tenth.

Find the value of x. Round to the nearest tenth.-example-1

2 Answers

2 votes

Answer:


\huge\boxed{x=14.2}

Explanation:

Use a cosine:


cosine=(adjacent)/(hypotenuse)

We have:


adjacent=12\\hupotenuse=x\\measure\ of\ angle=32^o

Look at the picture or use the calculator.


\cos32^o=0.8480

Substitute:


0.848=(12)/(x)\\\\(0.848)/(1)=(12)/(x)

cross multiple


0.848x=12

divide both sides by 0.848


x=(12)/(0.848)\\\\x=14.2

Find the value of x. Round to the nearest tenth.-example-1
User Greg Trevellick
by
8.3k points
5 votes

Answer:


cos\Theta =(adj)/(hyp)


cos 32=(12)/(x)


x=12/cos32


=14.2


OAmalOHopeO

User Whatupwilly
by
8.7k points

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