Answer:
Explanation:
you are being asked to "Solve a quadratic"
There are various METHODS to do this.
You will learn a few of them
-graphing
-substation
-complete the square
-quadratic formula
in this case the question wants you to solve it using the
Quadratic formula...
Ax^2 + Bx + C = 0 is the quadratic.
your A=-1 B=14, and C=61
you just have to plug in those numbers into:
±
![\sqrt{(B^(2)-4AC)/(2A)}](https://img.qammunity.org/2022/formulas/mathematics/high-school/gyj36v3sjq40ic97zwzgb7vwz3ykdc47na.png)
-14 ±
![\sqrt{(14^(2)-4(-1)(61))/(2(-1))}](https://img.qammunity.org/2022/formulas/mathematics/high-school/3cqg61v46ie49mwreqfaobsft14yftpg0o.png)
you should end up with 7+
& 7-
![√(110)](https://img.qammunity.org/2022/formulas/mathematics/high-school/23vd5qgsune81ygyx8lxbbf2drjin2xa88.png)
which is -3.49 or 17.49
-3.49 does not make any sense, the 17.49 distance only makes sense for this problem