21.4k views
1 vote
10 POINTS!! PLEASE HELP!!

10 POINTS!! PLEASE HELP!!-example-1

1 Answer

5 votes

Answer:

only the third answer is right.

Explanation:

to solve it, we need to bring everything to the same denominator (the expression below the division line) or eliminate it completely.

how do we do it ? by multiplying everything with the same expression, so that we can eliminate the denominator for every term.

when looking for the best option I see that

(x² + 5x + 6) = (x + 2)×(x + 3)

that is great, because this covers all 3 denominators in our main expression.

so, we multiply everything by ((x+2)×(x+3)) and eliminate the denominators and the corresponding part of our multiplier.

that leaves us with

x×(x+3) + 2 = 5×(x+2)

now we simply simplify the expression

x² + 3x + 2 = 5x + 10

x² - 8x - 8 = 0

a squared equation has typically 2 solutions. and they are defined as

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case

a = 1

b = -8

c = -8

x = (8 ± sqrt(64 + 32)) / 2 = (8 ± sqrt(96))/2 =

= (8 ± sqrt(16×6))/2 = (8 ± 4×sqrt(6))/2 = 4 ± 2×sqrt(6)

x1 = 4 + 2×sqrt(6)

x2 = 4 - 2×sqrt(6)

both solutions are different from -2 or -3, therefore -2 and -3 are not solutions at all, and they cannot be extraneous solutions either for that reason.

and since we have 2 perfectly fine solutions, the answer options work no or only one solutions are wrong too.

User Joshperry
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.