Answer: See explanation
Explanation:
Your question isn't well written, the store contains $227 and not $277.
let c be the number of $1 bills
let f be the number of $5 bills
let t be the number of $10 bills.
Therefore, the equation will be:
1c + 5f + 10t = 227
Since there are six more $5 bills than $10 bills, therefore,
f = t+6
Also, the number of $1 bills is two more than 24 times the number of $10 bills and this will be:
c = 24t + 2
Now, we substitute the equation for f and c into the main equation and this will be:
1c + 5f + 10t = 277
1(24t + 2) + 5(t + 6) + 10t = 227
24t + 2 + 5t + 30 + 10t = 227
39t + 32 = 227
39t = 227 - 32
39t = 195
t = 195/39
t = 5
Therefore, there are 5 $10 bills
Since c = 24t + 2
c = 24(5) + 2
c = 120 + 2
c = 122
Therefore, there are 122 $1 bills
Since f = t+6
f = 5+6
f = 11
Therefore, there are 11 $5 bills.