What is 125x^9+64y^12 written as sum of cubes?

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Delimiter · Answer 1 · 2022-03-10T05:37:03+0000

Answer:

Explanation:

125x^9 = (5x^3)^3

64y^12 = (4y^4)^3

If you want that factored it is

(5x^3 + 4y^4)( (5x^3)^2 - 5x^3*4y^4 + (4y^4)^2 )

(5x^3 + 4y^4)( 25x^6 - 20x^3y^4 + 16y^8)