Question

What is 125x^9+64y^12 written as sum of cubes?

Answer 1

Explanation:

125x^9 = (5x^3)^3

64y^12 = (4y^4)^3

If you want that factored it is

(5x^3 + 4y^4)( (5x^3)^2 - 5x^3*4y^4 + (4y^4)^2 )

(5x^3 + 4y^4)( 25x^6 - 20x^3y^4 + 16y^8)