Question

How many data values are closer than one mean absolute devitation away from the mean? 34,37,48,32,25,34,35,23,33,30. HELP ME PLEASE

Answer 1

First find the mean:
Which is the sum of all of the values divided by number of values.
Using online calc: mean = 33.1.
Now to find the MAD or mean absolute deviation: which is |value-mean| for each value.
For example abs(34-33.1) = 0.9 this is the absolute deviation. Now we do this for each point and find the mean of all of those values.
Using online calc we get Mad = 4.5
So one away from the mean up and down would be
37.6 — 28.6
So values one MAD away plus or minus would be: 34,37,32,34,35,33,30
Which is 7.