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4 votes
У = 3(х – 4)2 – 8
How do you write this in standard form

User Dunni
by
8.6k points

1 Answer

5 votes

Answer:


y = 3x^2-24x+40

Explanation:

Hi there!

Standard form:
y=ax^2+bx+c


y = 3(x-4)^2-8

Solve
(x-4)^2


y = 3(x^2-8x+16)-8

Multiply 3 by the parentheses


y = 3x^2-24x+48-8\\y = 3x^2-24x+40

I hope this helps!

User Reuben Thomas
by
8.3k points

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