Plz help I'll give brainy!!! Complete the missing parts of the table for the following function. y=(1/5)^x X-2 -1 0 1 2 3 y [?] [ ] 1 1/5. 1/? 1/125

Question

asked Mar 15, 2022 152k views

2 Answers

Clemesha · Answer 1 · 2022-03-20T18:33:41+0000

Answer:

see below

Explanation:

we are given a exponential function

$\displaystyle y = \left(1/5\right) ^(x)$

we want to figure out the missing values of y for x i.e (-2,-1, and 2) to do we can consider substituting so,

when x is -2 y should be

$\displaystyle y = \left(1/5\right) ^( - 2)$

rewrite ⅕ in exponent notation:

$\displaystyle y = \left((5) ^( - 1) \right) ^( - 2)$

by law of exponent we obtain:

$\displaystyle y = (5) ^( 2)$

simplify square:

$\displaystyle y = \boxed{ 25}$

when x is -1:

$\displaystyle y = \left(1/5\right) ^( - 1)$

rewrite ⅕ in exponent notation:

$\displaystyle y = \left((5) ^( - 1) \right) ^( - 1)$

use law of exponent which yields:

$\displaystyle y = \boxed5$

when x is 3:

$\displaystyle y = \left(1/5\right) ^( 3)$

by law of exponent we obtain:

$\displaystyle y = 1/ {5}^(3)$

simplify square which yields:

$\displaystyle y = \frac{1}{ \boxed{125}}$