Question

4. If 2 Cos A-1 = 0, then the value acute value A is​

Answer 1

A= 60






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Answer 2

`A=60^(\circ)`

Explanation:

Given
`2\cos A-1=0`,

Add 1 to both sides:

`2\cos A=1`

Divide both sides by 2:

`\cos A=(1)/(2)`

Take the inverse cosine of each side (note that the question stipulates that A is acute):

`\arccos(\cos A)=\arccos((1)/(2))`

`A=\arccos((1)/(2)), A\in (0^(\circ), 90^(\circ)),\\A=\boxed{60^(\circ)}`