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4. If 2 Cos A-1 = 0, then the value acute value A is​

User Melita
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A= 60






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User StanK
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Answer:


A=60^(\circ)

Explanation:

Given
2\cos A-1=0,

Add 1 to both sides:


2\cos A=1

Divide both sides by 2:


\cos A=(1)/(2)

Take the inverse cosine of each side (note that the question stipulates that A is acute):


\arccos(\cos A)=\arccos((1)/(2))


A=\arccos((1)/(2)), A\in (0^(\circ), 90^(\circ)),\\A=\boxed{60^(\circ)}

User Laurens Rietveld
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