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1 vote
Find a33 of the arithmetic sequence given a1=17 and d=6.

User Zyndor
by
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1 Answer

3 votes

Answer:

209

Explanation:

Given the following:


a_(1) = 17\\d=6

The nth term of an arithmetic sequence is expressed as:


a +(n-1)d

a is the first term = 17

d is the common difference =6

Get the 33rd term:


n=33\\a_(33)=17+(33-1)*6\\a_(33) =17+32(6)\\a_(33)=17+192\\a_(33)=209

Hence the 33rd term is 209

User Daniele Baggio
by
8.0k points

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