Question

The contraption below has the following

characteristics: m1 = 2.0 x 103 kg, m2 = 4.4 x 102 kg,
the man on top of m2 has a mass m = 6.0 x 101 kg,
and all surfaces are frictionless. What is the apparent
weight of the man?

Answer 1

The correct answer is "470.4 N".

Step-by-step explanation:

Let the system moves downwards with acceleration "a",

then,

⇒
`a = (Net \ external \ force)/(Net \ mass)`

`=((m_2+m)g)/((m_2+m_1+m))`

`=(440+60)/((440+2000+60))`

`=(500* 9.8)/(2500)`

`=1.96 \ m/s^2`

The apparent weight will be:

⇒
`mg-F_A=ma`

or,

⇒
`F_A=mg-ma`

`=m(g-a)`

By substituting the values, we get

`=60(9.8-1.96)`

`=470.4 \ N`