Question

Use the quadratic formula to find the solutions to the quadratic equation below. Check all that apply. 4x2-x-5 = 0

a.-1
b.-4/5
c.2/3
d.1
e.5/4
f.3/2​

Answer 1

a. -1

e. 5/4

Explanation:

Hi there!

The quadratic formula:
`x=(-b\pm√(b^2-4ac))/(2a)` where the given quadratic is in the form
`ax^2+bx+c=0`

From the given equation
`4x^2-x-5 = 0`, we can identify the values of a, b, and c:

a=4

b=-1

c=-5

Plug these values into the quadratic formula:

`x=(-(-1)\pm√((-1)^2-4(4)(-5)))/(2(4))\\x=(1\pm√(81))/(8)`

`x=(1\pm9)/(8)`

`x=(1+9)/(8)= (5)/(4) \\x=(1-9)/(8) = -1`

Therefore, the solutions to the quadratic are 5/4 or 1.

I hope this helps!