114k views
4 votes
Which expression gives the total number of gas particles (NOT moles, but individual particles) found in the lungs of an average human (V = 6.0 L) under normal physiological conditions (P = 1.0 atm, T = 37ºC)?

1 Answer

0 votes

Answer:


particles=1.42x10^(23)

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us solve this problem by using the ideal gas law:


PV=nRT

Which can be modified to include the particles in terms of the Avogadro's number:


PV=(particles)/(N_A) RT

Thus, if we solve for the particles, we will obtain the expression and the numerical result:


particles=(PV*N_A)/(RT)


particles=(1.0atm*6.0L*6.022x10^(23))/(0.08206(atm*L)/(mol*K)*310K) \\\\particles=1.42x10^(23)

Regards!

User Wsgg
by
4.4k points