Question

The Indianapolis speedway consists of a 2.5 mile track having four turns, each 0.25 mile long and banked at 9 12'

Answer 1

To calculate the ideal speed to take a steeply banked tight curve, we can use the formula Speed = square root of (radius * acceleration due to gravity * tangent(angle)). Plugging in the given values, we can calculate the speed.

Step-by-step explanation:

The question is asking about the ideal speed to take a steeply banked tight curve. In this case, we are dealing with a 100 m radius curve banked at 65.0°, assuming the road is frictionless. To calculate the ideal speed, we can use the formula:

Speed = square root of (radius * acceleration due to gravity * tangent(angle))

Plugging in the values for radius (100 m) and angle (65.0°), we can calculate the speed using this formula.

Answer 2

Answer: Your question is missing below is the question

Question : What is the no-friction needed speed (in m/s ) for these turns?

answer:

20.1 m/s

Step-by-step explanation:

2.5 mile track

number of turns = 4

length of each turn = 0.25 mile

banked at 9 12'

Determine the no-friction needed speed

First step : calculate the value of R

2πR / 4 = πR / 2

note : πR / 2 = 0.25 mile

∴ R = ( 0.25 * 2 ) / π

= 0.159 mile ≈ 256 m

Finally no-friction needed speed

tan θ = v^2 / gR

∴ v^2 = gR * tan θ

v = √9.81 * 256 * tan(9.2°) = 20.1 m/s