A certain first order reaction has a half-life of 54.3 s. How long will it take (in s) for the reactant concentration to decrease from 6.50 M to 2.27 M

Question

asked Jun 11, 2022 227k views

1 Answer

ZenLikeThat · Answer 1 · 2022-06-17T21:14:27+0000

Answer:

t=82.2s

Step-by-step explanation:

From the question we are told that:

Half life
t_(1/2)=54.3s

Change in concentration
$\triangle conc=6.50 M to 2.27 M$

Generally the equation for half life is mathematically given by

k=(2.303)/(t)*log(C_1)/(C_2)

Where

K=(0.693)/(t_(1/2))

K=(0.693)/(54.3)

K=0.0128

Therefore

0.0128=(2.303)/(t)*log(6.50)/(2.27)

t=82.2s