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Write a slope-intercept form of the equation if it passed the

point (4, -1) that parallel to
y= -3/4x

1 Answer

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Answer:


\sf\longrightarrow \boxed{\pink{\sf 3x + 4y -8=0}}

Explanation:

We need to write the slope intercept form of the equation which passes through (4,-1) and parallel to the line y = -3/4x .

We know that the line parallel to a given line has the same slope . Therefore the slope of the line will be , ( on comparing to Slope Intercept Form ) .


\sf\longrightarrow Slope =(-3)/(4)

On using point slope form ,


\sf\longrightarrow y-y_1= m ( x - x_1)

Substitute the respective values ,


\sf\longrightarrow y - (-1) = (-3)/(4)( x - 4 )

Simplify ,


\sf\longrightarrow y +1 = (-3)/(4)x + 3

Multiply both sides by 4 ,


\sf\longrightarrow 4y + 4 = -3x + 12

Put all terms on same side , i.e. on LHS ,


\sf\longrightarrow \boxed{\pink{\sf 3x + 4y -8=0}}

Hence the equation of the line is 3x + 4y - 8 = 0.

User Laconbass
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