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When CH3NO2 burns in excess oxygen, it forms carbon dioxide, nitrogen dioxide and water. How many moles of oxygen are required to burn 17.10 mole(s) of CH3NO2

1 Answer

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Step-by-step explanation:

The given reaction is the combustion of CH3NO2.

The balanced chemical equation of the reaction is:


4CH_3NO_2+ 7O_2 ->4 CO_2+4NO_2+6H_2O

So, from the balanced chemical equation, it is clear that:

4 moles of CH3NO2 --- 7 moles of oxygen gas is required.

then,

for 17.10 moles of CH3NO2 the following number of moles of oxygen is required.


The number of moles of O_2 required=17.10 mol. x (7 mol)/(4 mol) \\=29.925 mol

Answer is :

29.9 mol of oxygen gas is required.

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