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Helpppp meeeee outttttt pleaseeeee ASAPPPP!!!!

Helpppp meeeee outttttt pleaseeeee ASAPPPP!!!!-example-1

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Answer:


\boxed{\sf sin\ C =(40)/(41)}

Explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .


\sf\longrightarrow sin\theta =( perpendicular)/(hypontenuse)

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,


\sf\longrightarrow sinC =( p)/(h)\\\\\sf\longrightarrow sin\ C =(AB)/(AC)

Substitute the respective values ,


\sf\longrightarrow \boxed{\blue{\sf sin\ C =(40)/(41)}}

Hence the required answer is 40/41.

User Martell
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