Question

What is the answer to this problem
`(5y-20)/(3y+15) .(7y+35)/(10y+40)`

Answer 1

7(y-4)

---------

6(y+4)

Explanation:

5y-20 7y+35

------------ * ------------

3y+15 10y +40

Factor

5(y-4) 7(y+5)

-------- * -----------

3(y+5) 10(y+4)

Cancel like terms

(y-4) 7

-------- * -----------

3 2(y+4)

7(y-4)

---------

6(y+4)