Question

Which method is best to use to solve the equation 4x^2– 29 = 0?

Answer 1

`\huge\text{Hey there!}`

`\mathsf{4x^2 - 29 = 0}\\\\\large\textsf{ADD 29 to BOTH SIDES}\\\mathsf{4x^2 - 29 + 29 = 0 + 29}\\\\\textsf{CANCEL out: -29 + 29 because that gives you 0}\\\\\textsf{KEEP: 0 + 29 because that helps you solve for the x-value}\\\\\mathsf{0 + 29 = \bf 29}\\\\\textsf{NEW EQUATION: }\mathsf{4x^2 = 29}\\\\\large\textsf{DIVIDE 4 to BOTH SIDES}\mathsf{(4x^2)/(4)=(29)/(4)}\\\\\large\textsf{{CANCEL out:} }\mathsf{(4)/(4)}\textsf{ because that gives you 0}`

`\textsf{KEEP: }\mathsf{(29)/(9)}\large\textsf{ because that helps solve for the x-value}`

`\textsf{NEW EQUATION: }\mathsf{x^2=(29)/(4)}`

`\large\textsf{TAKE the SQUARE ROOT}`

`\mathsf{x = \pm \sqrt{(29)/(4)}}`

`\text{Random fact: if you see the symbol }\mathsf{\bf \pm}\text{ it usually means plus-or-minus.}\\\\\text{Okay, now lets answer the last step to your question!}`

`\mathsf{\sqrt{(29)/(4)}= \boxed{\bf 2.692582}}}\\\\\mathsf{OR}\\\mathsf{- \sqrt{(29)/(4)} =\boxed{ \bf -2.692582}}`

`\boxed{\boxed{\huge\textsf{Answer: \bf x = 2.692582 or x = -2.692582 }}}\\\huge\checkmark`

`\large\text{Good luck on your assignment and enjoy your day!}`

~
`\frak{Amphitrite1040:)}`