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What bet force is required to stop a 2250 kg car if the decelerates at a rate of -4.3 m/s^2 please answer fast

What bet force is required to stop a 2250 kg car if the decelerates at a rate of -4.3 m/s^2 please answer fast
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What bet force is required to stop a 2250 kg car if the decelerates at a rate of -4.3 m/s^2 please answer fast

User Kristoffer L
by
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1 Answer

3 votes

Answer:

Force = Mass × Acceleration


{ \tt{force = 2250 * 4.3}} \\ = { \tt{9675 \: newtons}}

User Aljoshare
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