Register

P=2L+2W; L=57, W=148 solve for P

P=2L+2W; L=57, W=148 solve for P
116k views
4 votes
P=2L+2W; L=57, W=148 solve for P

User Matthew Chung
by
7.9k points

2 Answers

2 votes

Answer:

P=410

Explanation:

2(57)+2(148)=114+296=410

User Fokkerplanck
by
8.0k points
2 votes

Answer:


{ \bf{P = 2L + 2W}} \\ { \tt{P = 2(W + L)}} \\ { \tt{P = 2(148 + 57)}} \\ { \tt{P = 410}}

User Ferhatelmas
by
8.1k points
← Prev Question Next Question →

Related questions

User Aoakenfo
asked Mar 2, 2017 193k views
P = 2l 2w to find the length of a rectangle whose perimeter is 57 inches and whose width is 13 inches.
Aoakenfo asked Mar 2, 2017
by Aoakenfo
7.4k points
2 answers
1 vote
193k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!