Question

If 225 cal of heat is added to 15.0 g of 2-propanol at room temperature, 25ºC, the alcohol will reach a final temperature of ________ ºC. The specific heat of 2-propanol is 0.612 cal/(g•ºC).

Answer 1

The alcohol will reach a final temperature of 49.5ºC when 225 cal of heat is added to 15.0 g of 2-propanol at room temperature.

Step-by-step explanation:

To calculate the final temperature of 2-propanol after adding 225 cal of heat, we can use the equation:

q = mcΔT

Where:
q = heat energy (in calories)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in cal/(g·ºC))
ΔT = change in temperature (in ºC)

Plugging in the given values:

225 cal = (15.0 g)(0.612 cal/(g·ºC))(final temperature - 25ºC)

Simplifying:

225 cal = 9.18(final temperature - 25ºC)

Dividing both sides by 9.18:

final temperature - 25ºC = 24.5

Adding 25ºC to both sides:

final temperature = 49.5ºC