Question

Identify The slope and y-intercept Of the equation Y= -8

Answer 1

to get the equation of any straight line we simply need two points off of it, hmmm let's use the points in the picture below.

`(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-8})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-8}-\stackrel{y1}{(-8)}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{(-1)}}}\implies \cfrac{-8+8}{5+1}\implies \cfrac{0}{6}\implies 0`

`\begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-8)}=\stackrel{m}{0}(x-\stackrel{x_1}{(-1)}) \implies y+8=0(x+1) \\\\\\ y+8=0x+0\implies y=\stackrel{m}{0} x\underset{b}{-8}\impliedby \begin{array}c \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}`