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What is the slope of the line that contains the points (13,-2) and (3,-2)? Be sure to simply result

1 Answer

9 votes

Answer:

0

Explanation:

m=(y2-y1)/(x2-x1)

m=(-2-(-2))/(3-13)

m=(-2+2)/-10

m=0/-10

m=0

User PVoLan
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