Question

Find side b, in triangle ABC. if angle B =42 degrees, a=6, c=4

Answer 1

There is no valid value for b

Explanation:

We solve the above question using the law of cosines

b² = a² + c² - 2ac × Cos B

B = 42°, a = 6, c = 4

b² = 6² + 4² - 2 × 6 × 4 × Cos 42

b =√6² + 4² - 2 × 6 × 4 × Cos 42

b = √36 + 16 - 48 × Cos 42

Solving the above question, there is no valid value for b