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Calculate the percent dissociation of crotonic acid (C,H,CO,H) in a 0.63 mM aqueous solution of the stuff.

1 Answer

1 vote

Answer:

16%

Step-by-step explanation:

Crotonic acid : C₃H₅CO₂H

C₃H₅CO₂H ⇄ C₃H₅CO₂⁻ + H⁺

C O O

where : C = C ( 1 - ∝ ) , O = C∝

also: Ka = C∝² / ( 1 - ∝ ) ---- ( 1 )

From Alexa data resource :

Pka = 4.69 , [ Ka = 2.04 * 10^-5 = C∝² / ( 1 - ∝ ) ]

back to equation 1

2.04 * 10^-5 = [ ( 0.63 * 10^-3 ) * ∝² / ( 1 - ∝ ) ] ----- ( 2 )

∴ ∝² / ( 1 - ∝ ) = 3.24 * 10⁻²

Resolving equation above

∝ = 0.1645 = 16.45%

Calculate the percent dissociation of crotonic acid (C,H,CO,H) in a 0.63 mM aqueous-example-1
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