Question

In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system. Kepler-12b, has a diameter that is 1.7 times that of Jupiter (RJupiter = 6.99 × 10^7 m), but a mass that is only 0.43 that of Jupiter (MJupiter = 1.90 × 10^27 kg ).

Required:
What is the value of g on this large, but low-density, world?

Answer 1

The acceleration due to gravity is 3.86 m/s^2.

Step-by-step explanation:

Radius , R = 1.7 x 6.99 x 10^7 m

mass, M = 0.43 x 1.9 x 10^27 kg

The acceleration due to gravity is given by

`g= (GM)/(R^2)\\\\g =(6.67* 10^(-11)* 0.43* 1.9* 10^(27))/((1.7* 6.99* 10^7)^2)\\\\g = 3.86 m/s^2`