Question

Anyone good with calculus? Please help.

Answer 1

First take a time derivative of a function describing motion,

`(d)/(dt)h(t)=(d)/(dt)-4.9t^2+19.6t-14.6=-9.8t+19.6`.

Finding the maxima of the function is obtained by determining where the critical points are. You can find the critical points by equating the derivative with 0 and solving for t,

`(d)/(dt)h(t)=0`

`-9.8t+19.6=0\implies t=(19.6)/(9.8)=\boxed{2}`.

So at 2 seconds the ball peaks in height.

To find out the height feed 2 to the function h.

`h(2)=-4.9\cdot2^2+19.6\cdot2-14.6=\boxed{5}`.

So at 2 seconds the ball reaches maximum height of 5 meters.

Hope this helps :)