Question

Find the equation of the straight line whose portion is bisected at (2, 3).​

Answer 1

Let P(2,3) be the point passes through the line

Let a,b be x-intersept and y-intersept of line respectively

∵ Point P(2,3) bisect the points (a,0) and (0,b)

∴ we have 2=(a + 0)÷2 and 3=(b + 0)÷2

∴a=4 and b=6

∴ by using intersept form

x/4+y/6=1

Graph :

Answer 2

Let P(2,3) be the point passes through the line

Let a,b be x-intersept and y-intersept of line respectively

∵ Point P(2,3) bisect the points (a,0) and (0,b)

∴ we have 2=a+02 and 3=b+02

∴a=4 and b=6

∴ by using intersept form

x4+y6=1

Explanation:

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