Question

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Answer 1

Find sides of aD and BC

AD:-

• √(1-3)²+(1-3)²
• √2²+2²
• √8

BC

• √(8-5)²+(1-3)²
• √(3)²+(-2)²
• √9+4
• √13

No it's not isosceles

Answer 2

• Not an isosceles trapezoid

Explanation:

Plot the given points.

We can see and visually confirm this is not isosceles.

(1,1) to (3, 3) distance is:

• 
  `AD = √((1-3)^2+(1-3)^2 ) = √(8) = 2√(2)`

(5,3) to (8, 1) distance is:

• 
  `BC = √((5-8)^2+(3-1)^2 ) = √(13)`

We see AD ≠ BC

The sides are not of the same length.