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the vertex of this parabola is at (2,-4). when the y-value us -3, the x-value is -3. what is the coefficient of the squared term in the parabolas equation?​

User Aswathi
by
6.2k points

2 Answers

3 votes

Answer:

-5

Explanation:

from a p e x

User Qxlab
by
5.1k points
0 votes

Answer:

The coefficient of the squared term is 1/25.

Explanation:

We are given that the vertex of a parabola is at (2, -4). We also know that y = -3 when x = -3.

And we want to determine the coefficient of the squared term of the equation.

Since we are given the vertex, we can use the vertex form of the quadratic:


\displaystyle y = a(x-h)^2+k

Where (h, k) is the vertex and a is the leading coefficient. The leading coefficient is also the coefficient of the squared term, so we simply need to find the value of a.

Since the vertex is at (2, -4), h = 2 and k = -4. Substitute:


\displaystyle y = a(x-2)^2-4

y = -3 when x = -3. Solve for a:


\displaystyle (-3) = a((-3)-2)^2-4

Simplify:


\displaystyle 1 = a(-5)^2\Rightarrow a = (1)/(25)

Therefore, our function in vertex form is:


\displaystyle f(x) = (1)/(25)\left(x-2)^2-4

Hence, the coefficient of the squared term is 1/25.

User Venkatesh Panabaka
by
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