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The bear population increases at a rate of 2% per year. If there are 1,200 bears currently, how many bears will there be in 10 years?

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\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1200\\ r=rate\to 2\%\to (2)/(100)\dotfill &0.02\\ t=\textit{elapsed time}\dotfill &10\\ \end{cases} \\\\\\ A=1200(1 + 0.02)^(10)\implies A=1200(1.02)^(10)\implies A\approx 1462

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