How many moles are in 79.6 grams of Fe2O3?

asked Sep 12, 2022 78.1k views

3 votes

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5 votes

Answer:

0.49847139613321184

Step-by-step explanation:

Fe2O3 in 1 mol is 159.6882.

Divide 76.9 by 159.6882.

Omar Shehab answered Sep 19, 2022

4.2k points

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