Question

A 0.4 m long solenoid has a total of 356 turns of wire and carries a current of 79 A. What is the magnitude of the magnetic field at the center of the solenoid?

Answer 1

B = 0.088 T

Step-by-step explanation:

Given that,

The length of a solenoid, l = 0.4 m

No. of turns of wire, N = 356

Current, I = 79 A

We need to find the magnitude of the magnetic field at the center of the solenoid. It is given by the formula.

`B=\mu_onI\\\\B=\mu_o (N)/(l)* I\\\\B=4\pi * 10^(-7)* (356)/(0.4)* 79\\\\B=0.088\ T`

So, the magnitude of the magnetic field at the center of the solenoid is 0.088 T.