Question

Let ƒ(x) = 5x2 – x + 1 and g(x) = –3x. Evaluate the composition (ƒ ∘ g)(1) .

Answer 1

D

Explanation:

We are given the two functions:

`f(x) = 5x^2-x+1 \text{ and } g(x) = -3x`

And we want to find:

`(f \circ g)(1)`

Recall that this is equivalent to:

`=f(g(1))`

Evaluate g(1):

`g(1) = -3(1) = -3`

Substitute:

`=f(-3)`

Evaluate f(-3):

`f(-3)=5(-3)^2-(-3)+1=49`

Therefore:

`(f \circ g)(1) =49`

Our answer is D.

Answer 2

49

Explanation:

ƒ(x) = 5x2 – x + 1 and g(x) = –3x

(ƒ ∘ g)(1)

First find g(1) = -3(1) = -3

Then find f(g(1) = f(-3)

f(-3) = 5(-3)^2 - (-3) +1 = 5(9) +3+1 = 45+4 = 49