Question

A simple machine has an IMA of 7. If the effort force of 5N is applied over a distance of 4m, what is the ideal resistance force, and how far does the load travel?a) Fr = 0.71 N and dr = 0.57 m.b) Fr = 0.71 N and dr = 28 m.c) Fr = 35 N and dr = 0.57 m. d) Fr = 35 N and dr = 28 m.

Answer 1

Option C

Step-by-step explanation:

From the question we are told that:

`IMA=7`

Effort force
`F_e=5N`

Effort distance
`d_e=4m`

Generally the equation for IMA is mathematically given by

In Terms of Distance

`IMA=(d_e)/(d_x)`

`7=(4)/(d_x)`

`d_x=0.57m`

In Terms of Force

`IMA=(F_x)/(F_e)`

`7=(F_x)/(5)`

`F_x=35N`

Therefore

`F_x=35N` and
`d_x=0.57m`

Option C