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Solve for all positive values of θ less than 360° ,
3 tan \theta+2 =-1

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\theta=225°,315°

Answer:

Solution given:


3 tan \theta+2 =-1

keeping constant term on one side


3Tan\theta=-1-2


Tan\theta=-3/3


Tan\theta =-1

Since tan is negative in third and fourth quadrant.


Tan\theta=Tan(180+45),Tan(360-45)


\theta=225°,315°

User Bhargav Chudasama
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