Question

Please help I learned this a while ago and forgot how to do it

Answer 1

The slope-intercept form is
`y=(1)/(2)x+(11)/(2)`

Explanation:

To find the slope, use

`m=(y^2-y^1)/(x^2-x^1)`

Replace the x and y values with the points.

`m=(7-5)/(3-(-1))`

Solve.

`m=(2)/(4)`

`m=(1)/(2)`

After that, find the y-intercept form.

Put the equation in point-slope form.

`y-5=(1)/(2)(x+1)`

Replace x with 0.

`y-5=(1)/(2)(0+1)`

`y-5=(1)/(2)`

Add 5 to both sides.

`y=5(1)/(2)`

Convert to improper fraction form.

The y-intercept is
`(11)/(2)`

Now finally, write in slope-intercept form. (y=mx+b)

m is slope, b is the y-intercept.