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Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0

User Matt Baer
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1 Answer

2 votes

Answer:


{ \tt{ {x}^(2) + {y}^(2) - 6x - 2y + 4 = 0 }}

Center:


{ \tt{(3, \: 1)}}

Radius:


{ \tt{radius = \sqrt{ {g}^(2) + {f}^(2) - c } }} \\ = √(36 + 4 - 4) \\ = 6 \: units

User Xinqiu
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